
Andrew M. answered 04/27/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
√(64x12y20)
= [82(x6)2(y10)2]
= 8x6y10
3√[(-27y48)/(81x4)]
= 3√[(-3y16)3/((3)(33)(x)(x3))]
= (-3y16)/[(3x)( 3√(3x))]
= -y16/[x(3√3x)]
9√(27x2) - 14√(108x2) + 2√(48x2)
= 9√[32(3)x2] - 14√(62(3)x2) + 2√42(3)x2
= 9(3x)√3 - 14(6x)√3 + 2(4x)√3
= 27x√3 - 84x√3 + 8x√3
= (27x - 84x + 8x)√3
= -49x√3
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try the last two using:
(a + b)2 = a^2 + 2ab + b^2
(a - b)^2 = a^2 - 2ab + b^2