Andrew M. answered 04/12/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
27p/(18p2 - 36p)
= 27p/[18p(p-2)]
Since denominator cannot be zero the excluded values are
p=0, 2
factor 9p out of numerator and denominator
= [9p(3)]/[(9p)(2)(p-2)]
= 3/2(p-2) or 3/(2p-4), p≠0,2