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Question

An object is projected into the air and reaches the maximum height of 800 feet. At this point it begins to drop straight down. Using the formula H=16t^2 + 800, where h is the height and t is the time in seconds, what is the height of the object after 3 seconds.

Answer 1

First, you need to fix the formula.  The correct formula is

 

h(t) = -16t² + 800

 

(The minus sign was missing in the t² term.)

 

h(3) = -16(3)³ + 800 = 656 feet