Mark M. answered 03/12/18
Tutor
4.9
(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
F(x) = ∫(from 0 to x)[(t-1)/(t2+9)]dt
By the Fundamental Theorem of Calculus, F'(x) = (x-1)/(x2+9)
F'(x) = 0 when x-1 = 0 (i.e., x = 1)
When x < 1, F'(x) < 0. So, F(x) is decreasing
When x > 1, F'(x) > 0. So, F(x) is increasing
Therefore, l and ll are both true
F"(x) = [(x2+9)(1) - 2x(x-1)] / (x2+9)2
= (-x2 + 2x + 9) / (x2 + 9)2
F"(0) = 1/9 So, lll is FALSE.
ANSWER: A