A total of 720 people attended the school basket ballgame. Adult tickets cost $2.50 each and student tickets cost $1.50 each. If $1220 worth of tickets were sol

Question

To be solved in algebra format

Answer 1

total number of tickets sold is 720.

How many tickets were adult and how many were student?

Let x = adult tickets and therefore (720 - x) = student tickets

 

If each adult ticket costs $2.50 and x tickets were sold, then the money from adult tickets = 2.50x

In the same way, the money from student tickets = 1.50(720 - x)

The total money from all tickets is given as $1,220.

 

Therefore

2.50x + 1.50(720 - x) = 1220

2.50x + 1080 - 1.50x = 1220

2.50x - 1.50x = 1220 - 1080

x = 140 adult tickets

720 - x = 580 student tickets

 

 

Answer 2

This is a common type of algebra problem. You're given two types of information and you can use two equations. The first thing to do is to determine the two equations to use.

In this case there are number of tickets sold and amount of money made.

 

The first equation is number of tickets sold, which includes adult and student

#(T)ickets=#(A)dult + #(S)tudent     ==   T=A+S

 

The second is money made

$(M)oney made total= $(From students) + $(From Adults)

 

These are your two base equations. Now you have to relate them, this is done using the price per ticket. As in 

$(From students)=#(S)tudent * (Price per student ticket) ... and the same for adult tickets

 

Now to fill in all the information from the question prompt

Total tickets=720

Price per adult ticket=$2.50

Price per student ticket=$1.50

Money made=$1220

 

The first equation becomes

720=A+S

 

The second equation becomes

1220=(A*2.5)+(S*1.5)

 

At this point you can use substitution to solve for the answer, which i'll leave for you.

The important parts to remember are

1)Determine each basic equation

2)Relate the equations (this means use the same variables in each; in this case we started with number of tickets or money made for adults/students and changed both equations to use number of tickets)

3)plug in all the info given and you should have a standard algebra problem, which should be solvable with substitution.