Mark M. answered 03/02/18
Tutor
4.9
(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let f(x) = 3x2 - x Then f'(x) = 6x - 1, f(2) = 10, and f(2+h) = 3(2+h)2 - (2+h)
So, the given limit is equivalent to limh→0[ (f(2+h) - f(2))/h] = f'(2) = 6(2) - 1 = 11