Bobosharif S. answered • 02/28/18

Mathematics/Statistics Tutor

2(y+x)-5(x-y)=-8 (solve for y)

2y+5y=-8+3x

y=(3/7)x-8/7 (slope is 3/7)

Now, we look for the equation of the line which is perpendicular to this one. This means that its slope should be -7/3 (perpendicularity condition k1=-1/k2) and it has the form: y=-(7/3)x+b. In addition, it passes through the point (-4, 12).

12=-(7/3)(-4)+b

b=12+28/3=64/3

y=-(7/3)x+64/3

7x+3y=64