If 34.19g of NaCl react with excess of AgNo3, how many molecules will be formed?

Question

Chemistry Question

Answer 1

How many molecules of WHAT?  I'll assume you are asking how many molecules of AgCl(s) will be formed.  And for the record, we should refer to them as formula units, but I'll use molecules for simplicity.

NaCl + AgNO₃ ==> NaNO₃(aq) + AgCl(s)

moles NaCl = 34.19 g x 1 mole/58.5 g = 0.584 moles 

moles AgCl formed = 0.584 moles NaCl x 1 mole AgCl/1 mole NaCl = 0.584 moles AgCl

molecules AgCl = 0.584 moles x 6.02x10²³ molecules/mole = 3.52x10²³ molecules