derivadas de la funcion y= sen x

Question

que derivadas sales de la funcion y= sen x

Answer 1

Hola que tal,

La derivada que sale de  y =sen x, es la siguiente

y' = cos x 

Si necesitas alguna otra ayuda en ingles o en espanol te puedes poner en contacto conmigo yo estoy aqui para poder ayudarte en el idioma que usted escoja. 

atentatment, 

Yonathan c

Answer 2

y = sin x

dy/dx = y'(x)

then  y'(x)= cos (x) ======================================================================== Prove: ========================================================================= [1] Definition of sin (x) = [e^(xi)-e(-xi)] / 2 [2] y'(x)= y'(e^xi)/2 - y'(e^-xi)/2 ========================================================================= [3] y(x) = e(xi), y'(e^xi) = y'(x)= e^(xi) [4] y(x)= e^(-xi), y'(e^-xi) = y'(x)=-e^(-ix) then, substituing [3] and [4] on [2] have [5] y'(x) = e^(xi)/2 - -e^-xi)/2 ==> [6] y'(x) = e^(xi)/2 + e^(-xi)/2 ==> [7] y'(x) = [e^(xi) + e^(-xi)]/2 ========================================================================== Definition y(x)= cos (x) =[e^(xi) + e^(-xi)]/2 ========================================================================== then [8] y'(x) = [e^(xi) + e^(-xi)]/2 = cos (x) y'(x)= cos (x) That is, For y(x) = sin (x), y'(x)= cos (x)

Answer 3

Unfortunately, I only speak English and Russian.

However, it seems that you mean that you want the derivative of the sine function, y = sin x.

In that case the answer is y' = cos x.