Andrew M. answered 02/08/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
slope: m = (change in y)/(change in x)
m = (-2-2)/(5-(-3)) = -4/8 = -1/2
Point slope: y - y1 = m(x-x1)
where m is slope and (x1, y1) is on the line.
Let's use (-3, 2) as (x1, y1)
y - 2 = (-1/2)(x-(-3))
y - 2 = (-1/2)(x + 3).
This is an equation of the line in point slope format.
You could also use (5, -2) as (x1, y1)
y - (-2) = (-1/2)(x - 5)
y + 2 = (-1/2)(x-5)
Both answers are correct. If you change them
to standard form, ax + by = c, they will be equal.
Look at first equation.
y - 2 = (-1/2)(x+3)
2(y-2) = -(x+3)
2y - 4 = -x - 3
x + 2y = 1
Look at second equation.
y + 2 = (-1/2)(x - 5)
2(y+2) = -(x-5)
2y + 4 = -x + 5
x + 2y = 1
As you can see, they are the same.