MARVIN Z.

asked • 01/20/18

A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory.

In how many seconds after the shot will cannonball be at the highest point?
 
 
In _______ seconds cannonball will be at the highest point. The highest point is __________.

1 Expert Answer

By:

Arturo O. answered • 01/20/18

Tutor
5.0 (66)

Experienced Physics Teacher for Physics Tutoring

Andrew M.

Note:  For a quadratic y = ax2 + bx + c
The vertex is at (-b/2a, f(-b/2a))
 
Given: y = -16t2 + 300t,  a = -16, b = 300, c = 0
 
-b/2a = -300/[2(-16)]
 
This is where Arturo got his first equation: t = -300/[2(-16)] sec = 9.375 sec
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01/20/18

Arturo O.

Thanks Andrew.
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01/20/18

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