slope of -5/3 through (0,-4)

Question

show work please

Answer 1

I assume you meant to say that you want the equation of a line with slope -5/3 that passes through (0,-4).  In slope-intercept form,

 

y = mx + b

 

m = -5/3

 

The given point (0,-4) is the y-intercept point, since x = 0.  Therefore,

 

b = -4

 

y = (-5/3)x - 4