
Andrew M.
asked 12/15/172,4 and 8,13 slope
2,4 and 8,13 slope
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1 Expert Answer

Mark B. answered 12/15/17
Tutor
New to Wyzant
PhD Candidate in Psychology: Experienced Math, Statistics, Tutor
Hello Andrew,
My sincere apologies for the delayed response. I had been offline for a few.
To determine the slope of a line given two pairs of coordinates, this is what you need remember:
The slope of the line through (x1. y1) and (x2,y2) where x1 ≠ x2 is:
y2 - y1
---------
x2 - x1
Therefore:
13 - 4
-------
8 - 2
9/6 = Slope
Do you need this as equation in slope-form?
My sincere apologies for the delayed response. I had been offline for a few.
To determine the slope of a line given two pairs of coordinates, this is what you need remember:
The slope of the line through (x1. y1) and (x2,y2) where x1 ≠ x2 is:
y2 - y1
---------
x2 - x1
Therefore:
13 - 4
-------
8 - 2
9/6 = Slope
Do you need this as equation in slope-form?
y - y1 = m(x - x1) <-------Do you know how we arrive at this equation?
y - 4 = (3/2)(x - 2) <-------This is the equation in point-slope form.
Simplify the equation to solve for y.
Please let me know if this helped you and I wish you a great day tomorrow.
y - 4 = (3/2)(x - 2) <-------This is the equation in point-slope form.
Simplify the equation to solve for y.
Please let me know if this helped you and I wish you a great day tomorrow.

Andrew M.
The slope is 9/6 = 3/2 ... not 9/7
(13-4)/(8-2) = 9/6
y - 4 = (3/2)(x-2) point slope form
2y - 8 = 3(x-2)
2y - 8 = 3x - 6
-3x + 2y = 2 standard format
2y = 3x + 2
y = (3/2)x + 1 slope intercept form
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12/15/17

Mark B.
Hello Andrew,
My deepest gratitude for you pointing out the typo. I would hope you know that I can subtract 2 from 8 and arrive at 6. This is however the second time this has occurred to me. I will exercise extreme caution because my fear is the student - despite my amending the answer ended up just taking the answer and running with it. I sincerely hope not.
My deepest gratitude for you pointing out the typo. I would hope you know that I can subtract 2 from 8 and arrive at 6. This is however the second time this has occurred to me. I will exercise extreme caution because my fear is the student - despite my amending the answer ended up just taking the answer and running with it. I sincerely hope not.
Report
12/15/17

Mark B.
Hello Again Andrew,
Is there a place on our site where we (you and I) can communicate - to your knowledge - with other tutors? Or, do we need to sign in as a student, despite our being a tutor. Just trying to land my feet here and would appreciate bouncing some ideas off of you or others in your spare time (if you have any). Thanks in advance for any information you may provide me. And again, much gratitude.
Is there a place on our site where we (you and I) can communicate - to your knowledge - with other tutors? Or, do we need to sign in as a student, despite our being a tutor. Just trying to land my feet here and would appreciate bouncing some ideas off of you or others in your spare time (if you have any). Thanks in advance for any information you may provide me. And again, much gratitude.
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12/15/17
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David W.
12/15/17