Solve Logarithms

Question

Solve Log₃27+Log₈1/8-Log₁₆4=Log₄x

Answer 1

log₃27+log₈(1/8)-log₁₆4=log₄x

log₃3³+log₈(8^[-1])-log₁₆(16^[1/2])=log₄x

3+(-1)-(1/2)=log₄x

(1 1/2)=log₄x

(3/2)=log₄x

4^(3/2)=x

(4^3)^(1/2)=x

(64)^(1/2)=x

8=x (the square root of 64 is 8)