Epress the quadtratic in standard form

Question

f(x)=1+6X-X^2

 

Please include x and y intercepts and very text and min value

Answer 1

For standard form, rearrange the terms in descending order, i.e. squared/linear/constant term.

Vertex is at x = -b/(2a).

The y intercept is (0,c) where c = 1 in this case.

The x intercepts are the zeros, and they can be found (if they exist) using the quadratic formula.

The vertex point will be the maximum since this parabola opens downwardly. Thee is no minimum!

 

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