Find the limit where t approaches infinity

Question

What is lim_{[t -> infinity]}  (5t² + 8t + 1)/(2 - 6t - 3t²)

Answer 1

lim_t→∞ [ (5t²+8t+1) / (2 - 6t - 3t²) ]

 

= lim_t→∞ [ (5 + 8/t + 1/t²) / (2/t² - 6/t - 3) ]

 

= (5+0+0)/(0-0-3) = -5/3