Mixed math review

Question

what is the equation of the with a slope of -1/2 that passes through the point (6,-6)

Answer 1

Hi Tyler,

 

Since you are given a point (6,-6) and a slope (-1/2), you can plug those values into the point-slope form of a line:

 

y-y1 = m(x-x1) 

 

Given:

m = -1/2

x1 =6

y1 = -6

 

We get:

 

y-(-6) = -1/2(x-6)

 

Simplify:

 

y + 6 = -(1/2)*(×-6)

y + 6 = -(1/2)x + (-1/2)*(-6)

y + 6 = -(1/2)× + 3

Solve for y:

 

Subtract 6 from both sides of the equation to get:

 

y + 6- 6 = -(1/2)x +3 -6

 

Simplify:

 

y = -(1/2)x - 3

 

This is the slope-intercept form of the line that passes through (6,-6) and has a slope of -1/2. 

 

Please feel free to message me with any questions! 

 

Best,

Molly

 

 

 

Answer 2

slope=-1/2 passing through point (6,-6)

y=mx+b

y=(-1/2)x+b

-6=(-1/2)(6)+b

-6=-3+b

-6+3=b

b=-3

y=(-1/2)x-3