Alg II - Quadratic equation in Standard Form

Question

Write a quadratic equation in standard form whose graph is tangent to the x-axis at -4 and goes through the point (6,30).

Answer 1

the graph is tangent to the x axis at -4

the vertex of the parabola is (-4,0)

y=a(x-h)²+k

y=a(x+4)²+0

the graph goes through the point (6,30)

30=a(6+4)²

30=a*100

a=30/100=3/10

y=(3/10)(x+4)²

y=(3/10)(x²+8x+16)

y=(3x²/10 +24x/10+48/10)

y=3x²/10+12x/5+24/5