Raymond B. answered 15d
Math, microeconomics or criminal justice
period = 1/5 of an hour
low = 40, high = 250
at time t=0 P=40
sinusoidal wave = P = f(t) = Asin(2pit/(1/5) + c) + D
where A = Amplitude = max -min all over 2 = 250-40)/2 = 210/2 = 105
D = mid line = max+min all over 2 = 290/2 = 145 = vertical shift
C = horizontal shift = -pi/2
B = 2pi/period = 2pi/(1/5) = 10pi
P = pressure = pounds per in^2 =
f(t) = 105sin(10pit -pi/2) + 145
at time t=0 P= 105sin(-pi/2) + 145 =105(-1) +145= 145-105= 40 lbs/in^2