If the sides of a square are increased by 3cm the area becomes 64cm

^{2 }-
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If the sides of a square are increased by 3cm the area becomes 64cm^{2 }

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>adding three the side, then squaring gives you area of square

x+3 = 8

>taking square root is easier here because 64 has a perfect square root

x=5

>Isolate the variable

-I am wondering though, if you mean the perameter as a whole is increased by 3, rather than just each side being increased by 3, as I've done here..

X - side of the original square:

( X+3 )^2 = 64

X^2 + 6X + 9 = 64

X^2 + 6X - 55 = 0

(X +11) ( X -5 ) = 0

X = -11 X =5/ answer

Test :

( 5+3 ) ^2 = 64

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