If the sides of a square are increased by 3cm the area becomes 64cm^{2 }
(X+3)^2 = 64
>adding three the side, then squaring gives you area of square
x+3 = 8
>taking square root is easier here because 64 has a perfect square root
x=5
>Isolate the variable
-I am wondering though, if you mean the perameter as a whole is increased by 3, rather than just each side being increased by 3, as I've done here..
>adding three the side, then squaring gives you area of square
x+3 = 8
>taking square root is easier here because 64 has a perfect square root
x=5
>Isolate the variable
-I am wondering though, if you mean the perameter as a whole is increased by 3, rather than just each side being increased by 3, as I've done here..
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