Andrew M. answered 11/20/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
15 possibilities since order doesn't matter.
CD 1 and CD 2 is same as CD 2 and CD 1
1 with 2,3,4,5,6 = 5 pairs
2 with 3,4,5,6 = 4 pairs
3 with 4,5,6 = 3 pairs
4 with 5,6 = 2 pairs
5,6 = 1 pair
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15 possible pairs
The formula for combinations of n things taken k at a time
nCk = [n(n-1)(n-2).... up to k factors]/k!
n = 6, k = 2
6C2 = [(6)(5)]/2! = 30/2 = 15
David W.
11/20/17