find the simplest polynomial with roots -4, 7 and sqrt3

Question

Solve this math problem, i have had trouble and need help with it please

Answer 1

Square roots come in pairs; so, -√3 is also a root. x = -4, x = 7, x = √3, x = -√3

x + 4 = 0, x - 7 = 0, x - √3 = 0, x + √3 = 0

(x+4)(x-7)(x-√3)(x+√3) = 0

(x² - 3x - 28)(x² - 3) = x⁴ - 3x³ - 31x² + 9x + 84 = 0