how would you solve x^2+6=20

Question

How would you solve this with an ending ordered pair?

Answer 1

Ulaiah,

 

If   y = x² + 6    , and Mark gave you the values of x that will give you y, then what are your two order pairs?  Shouldn't you evaluate the value of y at these solutions?

 

Since   x² + 6  is 20, then the value of y must be 20.  Therefore, the two ordered pairs are (-√14 , 20) and (√14 , 20).

Answer 2

An ordered pair requires an x and a y. You present only an x.

x² + 6 = 20

x² = 14

x = ±√14