A rectangular painting has an area of 1037 square inches. If the length is 10 inches more than three times the width, what are the dimensions of the painting?

Question

rectangle has area of 1037 s inches 

length is 10 inches more than three times the width

Answer 1

A = 1037 = LW = (3W + 10)W ⇒

 

3W² + 10W = 1037

 

3W² + 10W - 1037 = 0

 

Solve for W and get W = 17

L = 3W + 10 = 3(17) + 10 = 61

 

Width:  17 inches

Length:  61 inches