Mark M. answered 11/08/17
Tutor
4.9
(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
dc/dq = 0.012q2 - 0.6q + 90
C(0) = fixed cost = $7000
C(q) = ∫[0.012q2 - 0.6q +90]dq
= 0.004q3 - 0.3q2 + 90q + K
Since C(0) = 7000, we have K = 7000
So, C(q) = 0.004q3 - 0.3q2 + 90q + 7000
Average cost = C(q)/q
When q = 100, Average cost = C(100)/100 = $170 / unit