Jackson M.

asked • 11/05/17

Questions about probability (Condition/Binomial random variable)

You have identical 30 balls; 5 black, 10 purple, 15 orange balls in a box.
 
Q1.If we take a ball, we make a mark on it and put it back to the box. We take one ball at a time. What is the probability of taking at least one orange ball, if we do the operation 5 times? (A ball can be marked several times). You have to solve this question by using Binomial random variable. 

Q2.Conditions are the same with the Q1. But in this problem we will do the operation until we get a purple ball. What is the probability the exactly 5th marked ball was purple? (Note that first 4 were not purple)

Q3 Conditions are the same with the Q1. Find the minimum number of operations we need to have the probability of a orange ball being marked to be at least 0.98?

1 Expert Answer

By:

Kenneth S. answered • 11/05/17

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Jackson M.

I forgot to add.
You have identical 30 balls; 5 black, 10 purple, 15 orange balls in a box.
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11/05/17

Kenneth S.

Q1.  P(at least one orange, 5 trials) = 1 - P(no orange, 5 trials) = 1 - (½)5 which you may simplified as desired.
 
Q2. P(4 consec non-purple followed by 5th is purple) = (2/3)4(1/3).
 
I don't see the importance of the marking, as stated.  Nor do I see the need for Bernoulli trials (binomial distribution) here.
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11/05/17

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