Mark M. answered 10/16/17
Tutor
4.9
(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Margnal cost = C'(x) = (-x+10)2
C(x) = ∫C'(x)dx = ∫(-x+10)2dx Let u = -x+10
Then, du = -dx So, dx = -du
C(x) = -∫u2du
= -(1/3)u3 + K
= -(1/3)(-x+10)3 + K
Since C(0) = 0, we have -(1/3)(1000) + K = 0
K = (1/3)(1000)
So, C(x) = (-1/3)[(-x+10)3 - 1000]