J.R. S. answered 10/15/17
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
x = mg of the 1st powder
y = mg of the 2nd powder
Eq 1: (x)(0.2) + (y)(0.15) = 140 mg B1
Eq 2: (x)(0.3) + (y)(0.10) = 190 mg B2
Expanding Eq 1: 0.2x + 0.15y = 140
x + 0.75y = 700
x = 700 - 0.75y
Substituting into Eq 2:
(700 - 0.75y)(0.3) + 0.1y = 190
y = 160 mg of 2nd powder
(x)(0.2) + (160)(0.15) = 140
x = 580 mg of the 1st powder