How can I solve y= 6cos2x find y^(6)?

Question

I am trying to study specific calculus question but I am currently stuck.

Answer 1

y = 6cos2x

 

Do you mean y(6) or y⁶ ?  It it is the former, then

 

y(6) = 6cos[2(6)] = 6cos12, where 12 is in radians.

 

If it is the latter, then

 

y⁶ = 6⁶cos⁶(2x).

 

Or perhaps you meant y'(6) ?

 

y' = -12sin2x

 

y'(6) = -12sin12