Parallel and perpendicular

Question

An equation of a line through (11, -13) which is perpendicular to the line y=5x+2 has slope:_____ and Y-intercept at:____

Answer 1

Its slope must be the negative reciprocal of the slope of the given line.

 

m = -1/5

 

Knowing m and a given point, we can easily write the equation of the line in point-slope form.

 

y - y₁ = m(x - x₁)

 

y₁ = -13

x₁ = 11

 

y + 13 = (-1/5)(x - 11)

 

Set x = 0 to find the y-intercept b.

 

b + 13 = (-1/5)(0 - 11)

 

Solve for b.  You can finish from here.