write an equation for the line that is perpendicular to the given line and that passes through the given point
Y=-1/3x+2; (4,2)
write an equation for the line that is perpendicular to the given line and that passes through the given point
Y=-1/3x+2; (4,2)
The slopes of two perpendicular lines, when multiplied, have a product of -1. Therefore, given the eq of the line with a slope of -1/3, we can conclude that the perpendicular line will have a slope of 3.
so to start, our equation of interest is y=3x + b, where b is unknown.
Since we know that it passes through the point (4,2) we can plug the values of x and y into this equation to solve for b. 2 = 3*4 + b
2=12 + b
-10 = b
This gives the entire equation we are after: y=3x-10.
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