b((1+r)/r)(sY/A)=((1-ϴ)Y/N)
Multiply both sides by N, then by r/(1+r), then by A/bsY:
N= (1-θ)YAr/[(1+r))(b)(sY)]
N = ((1-θ)A/bs)·(r/(1+r))
Andrew S.
asked 10/04/17
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