Differentiate F(x)=3x^2-2cosx

Question

The is a calculus problem. Find the derivative of a trigonometric function

 

Answer 1

f(x) = 3x²-2cosx

 

df(x)/dx = d(3x²)/dx - d(2cosx)/dx           [This is the Sum Rule for derivatives]

 

Use the Power Rule to take the derivative of 3x².  Also, d(cosx)/dx = -sinx.  Hence:

 

df(x)/dx = 6x + 2 sinx

Answer 2

Derivative of F(x)= 6*x+2*sinx