evaluate this s-12÷t2 if s=36 and t=-2.

Question

i need to know how to evaluate this equation s−12÷t2 if s=36 and t=-2.

Answer 1

The problem is poorly stated.  I'm assuming it's:

 

(s-12)/t²

 

Since s=36 and t=2, plug those values into the expression:

 

(s-12)/t²

 

(36-12)/2²

 

The order of operations (PEMDAS) says to do the operations within the parentheses first:

 

(36-12)/2² = 24/2²

 

Do the exponent next:

 

24/2² = 24/4

 

Do the division last:

 

24/4 = 6