
Andy C. answered 09/12/17
Tutor
4.9
(27)
Math/Physics Tutor
----->
given: W is a subset AND a subspace of vector space V.
Then by theorem, W is not empty and is closed under addition and scalar multiplication.
<-----
given: W is a non empty subset of V equipped and endowed with the same operations as V;
W is closed under addition and scalar multiplication.
Then by the same theorem, W is a subspace.
http://linear.ups.edu/html/section-S.html
Note that since we are given the operations are closed on W, we do not
need to go through the rigorous proof of showing the operations are closed
on W. Otherwise we would have to let vector x and vector y be elements
of W and show that x+y is in W. Likewise, for scalar k, kx is also in W.
However, this was nicely given. The proof is worded identically to
the theorem.