When a raindrop falls in still air, its acceleration is given by g-0.5v, where g is ate acceleration due to gravity and v is the velocity. We then have a = dv/dt = g-0.5v.
a) Taking g as 10ms^-2, determine the velocity of the raindrop after two seconds if it starts falling from rest.
b) When the acceleration is less than 0.01mm s^-2, the raindrop will effectively be travelling at uniform velocity.
i) At what velocity does this situation arise?
ii) How long does it take to reach this state?
Just need to know the working out, thanks.