Mark M. answered 09/04/17
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let f(x) = lnx - x + √x
f is continuous on the interval [2,3].
f(2) = ln2 - 2 + √2 > 0
f(3) = ln3 - 3 + √3 < 0
By the Intermedite value Theorem, there is at least one number, c, between 2 and 3 such that f(c) = 0.
So, lnc - c + √c = 0
Therefore, lnc = c + √c