
Kenneth S. answered 09/04/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Follow the usual rule of interchanging x & y.
x = 4y / √(5y2+4)
squaring both sides and cross-multplying gives 5x2y2 + 4x2 = 16y2
and this leads to 4x2 = y2(16-5x2).
Solving for y gives y = ±2x / √(16-5x2).
So this "inverse" is not a function (fails vertical line test). You may choose to drop the - option in front, to make the inverse exist.
As always, it's advisable to CHECK THIS ALGEBRA because of the possibility of mistakes (including typing).