How far does the ball travel between the interval [1,1.5]?

Question

A ball is dropped from a resting state of t=0. The distance traveled after t seconds is s(t)=16t^2 ft.

Answer 1

s(1) = 16(1)² ft = 16 ft

 

s(1.5) = 16(1.5)² ft = 36 ft

 

d = s(1.5) - s(1) = (36 - 16) ft = 20 ft

 

d = 20 ft