the approvimate value of x that are soluations to f(x)=0 where f(x)=5x^2+8x+9

Question

the approximate value of x that are soluations to f(x)=0 where f(x)=5x^2+8x+9

Answer 1

Using the quadratic formula, we have that x= (-8±√(8²-4*5*9))/(2*5)=(-4±i√29)/5

 

I suppose rounding the radical and simplifying the expression into decimal format would qualify as the "approximate value" of x...

Answer 2

-_-

I read it wrong.

Go for Suneil P.'s answer.