Mark M. answered 08/31/17
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
p > 2w + 6
l = 15
2(w + l) > 2w + 15
2(w + 15) > 2w + 15
2w + 30 > 2w + 15
30 > 15
All possible widths shall solve!