Andrew M. answered • 08/28/17

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

An aircraft carrier made a trip to dry dock and back. The trip there took five hours and the trip back took nine hours. It averaged 8 mph faster on the trip there than on the return trip. What was the aircraft carrier's average speed on the outbound trip?

Distance = Rate*Time ... d = rt

Let r = outgoing rate:

There: d = 5(r+8)

Back: d = 9r

Since the distance is the same set the equations equal to each other:

9r = 5(r+8)

9r = 5r + 40

Finish solving for r to determine the outgoing rate of speed