Marie P.
asked 07/11/14-14x2+44x-6=0
Algebra problem
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3 Answers By Expert Tutors
Arthur D. answered 07/11/14
Tutor
4.9
(369)
Mathematics Tutor With a Master's Degree In Mathematics
-14x2+44x-6=0
14x2-44x+6=0
2(7x2-22x+3)=0
7x2-22x+3=0
(7x-1)(x-3)=0
7x-1=0
7x=1
x=1/7
x-3=0
x=3
Inactive Tutor answered 07/11/14
Tutor
New to Wyzant
If the problem asks to solve for x, you can also directly use the quadratic formula (derived from completing the square).
Inactive Tutor answered 07/11/14
Tutor
New to Wyzant
Factor out -14 :
-14(x2 - 44/14 x + 6/14) = 0
divide both sides by -14
(x2 - 44/14 x + 6/14) = 0
simplify the terms
(x2 - 22/7 x + 3/7) = 0
solve by completing the square. Move the 3/7 term to the right side of the equation
x2 - 22/7 x = -3/7
Take half if the term with x : -22/7 and square it: (-11/7)2 = 121/49
now add 121/49 to both sides:
x2 - 22/7x + 121/49 = 121/49 - 3/7
Simplify the right side
x2 - 22/7x + 121/49 = 100/49
write the expression on the left as a square
(x - 11/7)2 = 100/49
and take the square root of both sides
x - 11/7 = 10/7 positive root
x - 11/7 = -10/7 negative root
solve for x
x = 10/7 + 11/7 = 21/7 = 3 or
x = -10/7 + 11/7 = 1/7
so the two possible solutions are x = 3 or x = 1/7.
Plug these numbers back into the original equation to verify the answers.
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David W.
07/11/14