Arturo O. answered • 08/17/17
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Let T be the temperature where °F = °C. Then
T = (5/9)(T - 32)
T = (5/9)(T - 32)
(9/5)T = T - 32
(9/5 - 1)T = -32
T = -32/(9/5 - 1) = -32(5/4) = -40
°C = °F only at -40°
°C = °F only at -40°
Arturo O.
Assuming you are OK through
(9/5 - 1)T = -32,
Solve for T and get
(9/5 - 5/5)T = -32
[(9 - 5)/5] T = -32
(4/5)T = -32
T = (5/4)(-32) = -40
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08/17/17
Daley N.
Thank you
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08/17/17
Arturo O.
You are welcome, Daley.
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08/17/17
Kenneth S.
Factoid: 16oC ≈ 61oF
A convenient palindrome for converting temperature on a typical late spring day in Sweden.
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08/17/17
Arturo O.
Yes, 16ºC is very close to 61ºF, but they are exactly the same only at -40º.
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08/17/17
Arturo O.
Ignore my last comment above. I thinking about something else.
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08/17/17
Daley N.
Alright got it
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08/17/17
Daley N.
08/17/17