An open top for the box gives all 1800 square centimeters of material
to the four "walls" and the "floor" of the box.
Build the Equation For Surface Area as:
Surface Area Equals [Length Times Length] (since the base is a square)
Plus [4 Times Length Times Height].
Rewrite Surface Area as A = L2 + 4LH.
Build the Equation For Volume as:
Volume = Height Times [Length Times Length].
Rewrite Volume as HL2.
Now equate 1800 to L2 + 4LH and write {1800 − L2}/4L = H.
Rewrite H as 450/L − L/4.
This renders Volume equal to:
V = L2[450/L − L/4] or 450L − L3/4.
Take dV/dL as 450 − (3/4)L2.
Equate 450 − (3/4)L2 to 0 which forces L2
to 600 and L to √600.
Then take the Maximum Volume sought as
450√600 − (√600)3/4 which goes to
7348.469228 cubic centimeters.
Taking d2V/dL2 or (-6/4)L and calculating -6/4 × √600 gives -1.5√600,
which is less than 0 and indicates a maximum volume at L = √600
as opposed to a minimum.