
Andy C. answered 07/30/17
Tutor
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Math/Physics Tutor
THe test statistic is :
X-bar - U
-------------
stdev/square-root(N)
X-bar is the sample mean which is 4 minutes
the population mean, per status quo, is 3.75
the standard deviation is 0.75
n = 50
so the test statistic is ( 4 - 3.75) / (0.75/square-root(50) = 2.35
The 95% confidence level means, the rejection threshold cutoff
is 1.96.
The test statistic is greater, so yes, there is statistical evidence
that the average lengths of the 50 songs in this sample
is "different" , or greater than the norm