Mark M. answered 07/27/17
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = (x-6)/(x+6)
f'(x) = [(x+6)(1) - (x-6)(1)]/(x+6)2 = 12/(x+6)2
f'(x) > 0 for all x ≠ -6
f is increasing on (-∞, -6) ∪ (-6, ∞)
f is never decreasing
There are no relative extrema.