Mark M. answered 07/13/17
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
limx→∞ [√(7+7x2)/(9+5x)] = limx→∞ [√(x2)√(7/x2 + 7)/(9+5x)]
= limx→∞ [x√ (7/x2+7)/(x(9/x+5))]
= limx→∞ [√(7/x2+7)/(9/x+5)]
= √(0+7)/(0+5) = √(7)/5
Michael J.
Both questions are the same type. Just different numbers. If you understand how one question is done, then you can do the other with ease. Just follow the procedure that Mark provided you.
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07/13/17
Mark M.
tutor
As x approaches negative infinity, √(x2) = -x, so the limit would be -√7/5.
There are 2 horizontal asymptotes, y = √7/5 (as x→∞) and y = -√7/5 (as x→-∞).
Mark M (Bayport, NY)
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07/13/17
Hussein H.
07/13/17