The slope of the tangent line is equal to the derivative of the function, evaluated at the given x-value. By applying power rule, we find the derivative of f(x) to be f'(x)=3x2-3. At your given x-value then, the slope is f'(3)=3(3)2-3=27-3=24.
Nhu B.
asked 07/10/17Find slope of tangent line
Find slope of tangent line at point (3,17) on function f(x)=x^3-3x-1
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