x² + 2x - 5 = 0
x² + 2x = 5
x² + 2x + 1 = 5 + 1
(x + 1)² = 6
x + 1 = ±√6
x = ±√6 - 1
The two solutions are (√6 - 1) and (-√6 - 1)
Ceejay J.
asked • 06/23/17Solve by completing the square
x^2+2x-5=0
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Michael J.
06/23/17